Question

The number of ways in which all the letters of the word “COCONUT” can be arranged
such that at least one C comes at odd place, is
1) 240
2) 360
3) 720
4) 1080​

Answer 1

Answer:

2). 360.............................

Answer 2

Answer:d

Step-by-step explanation:

COCONUT contains 7 words out of which there are 2 o and 2 c

No of ways in which COCONUT word  is arranged  is $=\frac{7!}{2!\cdot 2!}$

There are 3 even place in word coconut

No of ways in which c comes at even places

$=^{3}C_2\times \frac{5!}{2!}$

Total no of ways in which at least C comes at odd places=Total ways-No of ways in which C comes at even places

$=1260-\frac{360}{2}$

$=1080$