the number of ways in which first, second and third prizes can be given to 5 competitors
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2
Answer:
There are 5 choices of prize for the first person, 4 choices for the second, and so on. The number of ways the prizes can be distributed will be 5! = 5 · 4 · 3 · 2 · 1 = 120 ways.
Answered by
0
Answer:
60 ways
Step-by-step explanation:
There are 3 prizes that need to be given to 5 people.
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