The number of ways of wearing 6 different rings to 5 fingers is
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Let F = 5c0 + 5c1 + 5c2 + 5c3 + 5c4 + 5c5
R = 6c0 + 6c1 + 6c2 + 6c3 + 6c4 + 6c5 + 6c6
So answer is F×R
R = 6c0 + 6c1 + 6c2 + 6c3 + 6c4 + 6c5 + 6c6
So answer is F×R
Answered by
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6 is the answer............
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