Question

The number of years after which a sum of rupees 50000 will become rupees 55125 at CI rate of 5% is what

Answer 1

Given

Sum(p)= 50000rupees.

Amount= 55125rupees

Rate of interest= 5%

Time=?

FORMULAE USED

${\boxed{\rm{\blue{A=P(1+\dfrac{R}{100})^n}}}}$

Where,

A= Amount

P= Sum

R= Rate of Interest

n= Time.

$\implies\rm\blue{A=P(1+\dfrac{R}{100})^n}$

$\implies\rm\blue{55125=50000({1+\frac{5}{100})^n}}$

$\implies\rm\blue{\dfrac{55125}{50000}=\dfrac{105}{100}^n}$

$\implies\rm\blue{\dfrac{105}{100}^2=\dfrac{105}{100}^n}$

$\implies\rm\blue{n=2}$

Hence, The time will be 2 Years.

Answer 2

♻️ QUESTION ♻️

The number of years after which a sum of rupees 50000 will become rupees 55125 at CI rate of 5% is what?

♻️ ANSWER ♻️

✏️GIVEN✏️

✍️Sum of rupees(P)=50000

✍️ total amount (A)=55125

✍️Rate of interest (r)=5%

♻️ FORMULA ♻️

A=P(1+R/100)^n

apply in formula:!!!!

$55125 = 50000(1 + \frac{5}{100} ) ^{n}$

${( \frac{105}{100}) }^{n} = \frac{55125}{50000}$

${( \frac{105}{100}) }^{2} = \frac{11025}{10000} = {( \frac{105}{100}) }^{2}$

✴️comparing the exponents.✴️

⭐time period (n) is 2⭐