Question

the number of zero x²+4x+2​

Answer 1

Answer:

${x}^{2} + 4x + 2 = 0 \\ D= {b}^{2} -4ac \\ = {4}^{2} - 4 \times 1 \times 2 \\ = 16 - 8 \\ = 8 \\ \rightarrow have \:a \: unique \: solution \\ x=\frac{-b± \sqrt{D} }{2a} \\ = \frac{-4± \sqrt{8} }{2} \\ = \frac{-4±2 \sqrt{2} }{2} \\ = \frac{2(- 2± \sqrt{2}) }{2} \\ = - 2± \sqrt{2} \\ = - 2 + \sqrt{2} \: \: \: \: , \: \: \: \: - 2 - \sqrt{2} \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$