Question

The number of zeroes at the end of 124 factorial is can you also share the formula please.............

Answer 1

Answer:

28 zeros

Step-by-step explanation:

124! ends with [1245] + [12425] = 24 + 4 = 28 zeros

FORMULA IS IN THE ATTACHMENT ABOVE

Answer 2

Answer:

The number of zeroes at the end of 124 factorial is 28

Concept:

The product of a whole number 'n' with every whole number preceeding 'n', is called the factorial. Factorial of a number 'n' is given as;

$n! = n*(n-1)*(n-2)*(n-3).....*1$

For example, the factorial of 5 is $5!= 5*4*3*2*1= 120$

To calculate the number of trailing zeroes at the end of n!, we use the formula, $\frac{(n)}{5} + \frac{(n)}{25}$

For example, the number of trailing zeroes at the end of 159!

$\frac{159}{5} + \frac{159}{25}\\= 31.8 + 6.36\\(Rounding\ off)\\\\= 31+6\\= 37$

Therefore, 37 zeroes at the end of 159!

Given:

Factorial of 124

Find:

The number of zeroes at the end of 124!

Solution:

Factorial of 124 is calculated

$No.\ of\ trailing\ zeroes\ at\ the\ end\ of\ 124! = \frac{124}{5} + \frac{124}{25}\\= 24 + 4 \\= 28\ zeroes$

The number of zeroes at the end of 124 factorial is 28.