Question

the number of zeroes of polynomial p (x)=(x-2)^2+4 are​

Answer 1

Answer:

p(0)=4

Step-by-step explanation:

Given----->

p(x)=(x-2)²+4

$if \: x = 0 \\ \\ as \: per \: condition \\ \\ p(0) = {(x - 2)}^{2} + 4 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = {(0 - 2)}^{2} + 4 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = 0 + 4 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \\ \\ p(0) = 4$