Math, asked by girl1540, 7 months ago

the number of zeroes of polynomial Q(y) =(2y-3) (y+2) (y-√2) is​

Answers

Answered by sathyamargerate0410
0

Answer:

3

Step-by-step explanation:

Q(y)=(2y-3)(y+2)(y-√2)

Zeroes of Q(y)=3/2,-2,√2

No. of zeroes of Q(y) is 3

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