Question

The number of zeroes of the polynomial f(x) = (x - 3)² + 1 are ; (a) 0 (b) 1 (C) 2 (d) 3 ​

Answer 1

Answer:

option C is correct✔ ( 2 )

Step-by-step explanation:

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Answer 2

Answer:

0

Step-by-step explanation:

f(x)= (x-3)²+1

f(x)= x²+9-6x+1

f(x)= x²-6x+10

D = b²-4ac [b= -6 , a=1 , c=10]

D = (-6)²-4(1)(10)

=36-40

= -4

D<0

Therefore the equation has no real roots.