The number of zeroes of the polynomial P(x)=6x²-7x-3is
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Answer:
Step-by-step explanation:
0=6x²-7x-3
0=6x²-9x+2x-3
0=3x[2x-3] + 1[2x-3]
0=[3x+1] [2x-3]
[3x+1]=0 or [2x-3]=0
x = -1/3 or x = 3/2
hope it will help you
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