Question

The number of zeroes that polynomial f(x) = (x – 2)2 + 4 can have is: *

Answer 1

Answer:

Hence, The number of zeros the given polynomial (x - 2)² + 4 has = 2

Step-by-step explanation:

The polynomial is given to be : (x - 2)² + 4

To find the number of zeros of the polynomial we first simplify the given polynomial

⇒ (x - 2)² + 4

⇒ x² + 4 - 4x + 4

⇒ x² - 4x + 8

So, It can be seen that the degree of the given polynomial is 2

So, It can have 2 zeros

Hence, The number of zeros the given polynomial (x - 2)² + 4 has = 2

Please mark me as brainlist if it helps you.

Answer 2

p(x) = (x - 2)2 + 4  

p(x) = x2 - 4x + 4 + 4

p(x) = x2 - 4x + 8

If we find discriminant = b2 - 4ac we get b2 - 4ac < 0

Hence, the given quadratic polynomial has no real roots.