Question

The number of zeroes that polynomial f(x) = (x – 2)2 + 4 can
have is:
(i) (i) 1 (ii)2 (iii)0 (iv)3
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Answer 1

Answer:f(x) =(x-2)2+4

X=0

F(0)= (0-2)2+4

= (-2)2+4

= - 4+4

= 0

X=1

F(1)= (1-2)2+4

= (-1)2+4

= - 2+4

= 2

X=2

F(2)= (2-2)2+4

= (0)2+4

= 0+4

= 4

X=3

F(3)= (3-2)2+4

= (1)2+4

= 2+4

= 6