Question

The number of zeroes that polynomial f(x) = (x – 2)² + 4 can have is​

Answer 1

Answer:

(x-2)²+4

x²+4-4x+4

x²-4x+8

comparing with ax²+bx+c=0

a=1 , b=-4 , c=8

D=b²-4ac

D=(-4)²-4×1×8

D=16-32

D=-16

D<0

Hence , No real roots exist

Thus , can't find root

Step-by-step explanation:

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