Question

The number of zeroes, the polynomial f(x) = (x - 3)² + 1 can have is​

Answer 1

Step-by-step explanation:

HERE P(X) IS A QUADRATIC POLYNOMIAL AND QUADRACTIC POLYNOMIAL HAVE ATMOST 2 ZEORES SO THE NUMBER OF ZEORES F(X) HAVE ARE ATMOST TWO(2).

HOPE IT HELPS......

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Answer 2

Concept:

The polynomial equations of degree two in one variable of type f(x) = ax² + bx + c = 0 and with a, b, c, and R R and a 0 are known as quadratic equations. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f (x). The roots of the quadratic equation are the values of x that fulfil the equation (α,β ).

It is a given that the quadratic equation has two roots. Roots might have either a real or imaginary nature.

Given:

f(x) = (x - 3)² + 1

Find:

The number of zeroes, the polynomial f(x) = (x - 3)² + 1 can have is​

Solution:

f(x) = (x - 3)² + 1

(x-3)²+1=0

Since it is quadratic equation, the maximum zeroes it can have is 2

Let me show you,

(x-3)²+1=0

(x-3)²=-1

(x-3) = √-1

x= 3±i

So there are two roots

Therefore, f(x) = (x - 3)² + 1 can have two zeroes

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