The number of zeroes, the polynomial f(x) = (x – 3)² + 1 can have is:
(a) 0
(b) 1
(c) 2
(d) 3
So like the correct option given in the answer sheet is opt (a)
But we can have 2 imaginary roots
(Imaginary roots isn't in our syllabus but it can be considered)
So what's gonna be the appropriate answer?
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political in a way to get a job and the other people are going back to the point
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