Question

the number of zeros in the product of the first hundred natural number is

Answer 1

Since Count all the multiples of 5 in here => 5, 10, 15, 20, 25, ......., 100.
Now all of multiples of 5 are divisble by 5^1,5^2 (but not 5^3 as5^3=125>100)]
So the total umber of zeros in the product = Zeros in non-factorial part + zeros in factorial part i.e. 100 + 24 =124.