Question

the number of zeros of polynomial 3x^3-2x^2+x-1 is
(a) 2
(b) 3
(c) 4
(d) 1​

Answer 1

$\huge{\mathcal{\blue{\underline{Answer}}}}$

$\huge{\mathcal{\blue{\implies{\underline{3(correct)}}}}}$

Answer 2

-1 is the right

Hi,

Given polynomial is f(x) = 3x³ - 2x² - 7x - 2

Consider f(2) = 3.(2)³ - 2(2)² - 7(2) - 2

= 3.8 - 8 - 14 - 2

= 0

Hence , 2 is the zero of the polynomial.

Consider f(-1/3)

= 3.(-1/3)³ - 2(-1/3)² - 7(-1/3) - 2

= -3/27 - 2/9 + 7/3 - 2

= -1/9 - 2/9 + 7/3 - 2

= -3/9 +7/3 - 2

= 2 - 2 = 0

Hence, -1/3 is the zerof of f(x).

We Know Sum of zeros of f(x) is -ve of coefficient of x²/Coefficient of x³

=> 2 -1/3 + p = 2/3

=> p = -1

Thus, -1 is the third zero of the polynomial.

Hope, it helped !

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