Question

the number so obtained.
Find the least number of six digits which is a perfect square. Find the square re
of this number.​

Answer 1

Answer:

Nearest perfect squares to 10 are 9 and 16. 9=3^2 and 16=4^2. so,√10 lies between 3 and 4. Now, to be the smallest number of six digits, the number must be greater than (316.23^2) and it's square root must be an integer.

Step-by-step explanation:

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Answer 2

Nearest perfect squares to 10 are 9 and 16. 9=3^2 and 16=4^2. so,√10 lies between 3 and 4. Now, to be the smallest number of six digits, the number must be greater than (316.23^2) and it's square root must be an integer.

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