the number solution of root 3x+x+5=x-3
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Now, 3x
2
+x+5⩾0
This is because b
2
−4ac=1−4×5×3
=−59 (roots are imaginary)
3x
2
+x+5=(x−3)
2
=x
2
+9−6x and x−3⩾0
2x
2
+7x−4=0
2x
2
+8x−x−4=0
2x(x+4)−1(x+4)=0
(2x−1)(x+4)=0
x=
2
1
and−4 but x≥3
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