Question

The number that should be added to both the numerator and denominator of 5^2/7^2
so that the fraction
becomes 5/7 is
(a) 31
(b) 25
(c) 35
(d) not possible​

Answer 1

Answer:

C, 35

Step-by-step explanation:

If our original fraction is 25/49, and if we add a random number (x) to both numerator and denominator it will be 25+x/49+x=5/7. We then cross multiply, (25+x)*7=(49+x)*5, after simplifying the equation should be 175+7x=245+5x, then 2x=70, then x=35. If you plug it in 25+35=60, and 49+35=84. 60/84 (divide numerator and denominator by 12) is equal to 5/7.