Question

. The number which is to be added to 0.10 to get

​

Answer 1

Answer:

you add V ml of 0.1 M H

2

SO

4

then you are adding 0.01 moles of H

2

SO

4

.

in 50mL of 0.1 M NaOH, there are 0.005 moles of NaOH.

The chemical equation for that is :

2NaOH+H

2

SO

4

→Na

2

SO

4

+2H

2

O.

0.0025 moles of H

2

SO

4

will neutralize 0.005 moles of NaOH.

So from 0.01V moles of H

2

SO

4

added in VmL there will be

0.01V- 0.0025 moles of H

2

SO

4

left unused in the total volume of V + 50mL of solutions.

The conc. here will be

V+50

0.01V−0.0025

×1000=0.05M.

V+50

100v−2.5

=0.05

On solving for V, we get the value :

V = 0.05002 L

V = 50.02 mL