Math, asked by rohth3863, 1 year ago

The numbers 11284 and 7655, when divided by a certain number of three digits, leave the same remainder. find that number of three digits.

Answers

Answered by Anonymous
67
hey genuis ....


You have to find a three-digit number X such that 11284 / X and 7655 / X leave the same remainder R. In other words: 

(Equation 1) mX + R = 11284 

(Equation 2) nX + R = 7655 

Where m and n are whole number multiples. We want to combine the equations, so we'll make Equation 2 negative throuhout. That'll eliminate the remainder so we can focus more on X. 

(Equation 2.1) -nX - R = -7655 

Now we combine the equations to get: 

(Equation 3) (m - n)X = 11284 - 7655 

(Equation 3.1) (m - n)X = 3629 

m and n are whole numbers, and since mX + R is greater than nX + R, it follows that m is larger than n; therefore, m - n is also a whole number. Let's call it z. 

(Equation 4) zX = 3629 

To find X, we have to be able to find three-digit factors of 3629. Start by finding the smallest prime number that will divide evenly into 3629. 2 won't, 3 won't, 5 won't, 7 won't, 11 won't, 13 won't, 17 won't, but 19 will. 19 x 191 = 3629. And as it turns out, that makes X a three-digit number, so it satisfies your requirements and we can stop searching. 

To check, divide 11284 and 7655 by 191 to confirm that they give the same remainder: 

11284 / 191 = 59 R15 

7655 / 191 = 40 R15 

I hope that helps.
Answered by Anonymous
32

Answer:

Step-by-step explanation:

Total Numbers = 2 (Given)

Number one = 11284 (Given)

Number two = 7655 (Given)

Let the remainder in each case be = x

Thus, then (11284 - x) and (7655 - x) are exactly  divisible by that three digit number.

Therefore, the difference will be =(11284−x)−(7655−x)=3629

= 19×191

Three digit no. = 191

Sum of digits of the three digit number = 1 + 9 + 1 = 11

Thus, the required sum of digits of such a three-digit number is 11.

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