Math, asked by eisha6137, 9 months ago

the numbers 120 and 126 written as the products of their prime factors are 120 is equal to 2 cube into 3 into 5 and 126 is equal to 2 into 3 square into 7 hands find the smallest whole number that is divisible by both 120 and 126​

Answers

Answered by abhay919
1

Answer:

prime factors karke 120 ka phir 2 and 3 se division karna h

Similar questions