The numbers 176 and 342, written as the products
of their prime factors, are 176 = 24 x 11 and
342 = 2 x 32 x 19. Hence, find the smallest whole
number that is divisible by both 176 and 342.
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Answer:
2×2×2×2×11×3×3×19
=30608
HCF of 176 and 342 is 30608
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