Question

the numbers 23794 and 25273 are divided by a number x such that 50<x>100, than the remainder in each case is Y. Find Value of (x-y)?​

Answer 1

Answer:

Step-by-step explanation:

As per problem,

25273-23794=1479 is divisible by x.

Now

1479=3×17×29, therefore x=51 and 87, since greater than 50.

Therefore y=28 since 23794=51×466+28

And y=43 , since 23794=87×273+43

Answer 2

Values of x - y  = 23  & 44

Step-by-step explanation:

the numbers 23794 and 25273 are divided by a number x   such that remainder = Y

    25273 - Y = xA    Eq1

   23794 - Y  = xB    Eq2

A & B are integers

Eq1 - Eq2

=>   (25273 - Y) -    (23794 - Y) = xA - xB

=>  25273 - 23794   = x(A - B)

=>  1479 = xC   ( c is an integer) C = A - B

1479 = 3 * 17 * 29

=> 1479   = 51 * 29   or  87 * 17

x = 51   or  87

if x = 51  then Y  = 28

  x = 87  then Y = 43

x - y = 51 - 28 = 23

          87 - 43  = 44

Values of x - y  = 23  & 44

Learn more:

When a number is divided by 457 the remainder is 38 and if the ...

https://brainly.in/question/9975033

Let x be a least number which when divided by 21,33,35 and 55 ...

https://brainly.in/question/8888731