Question

The numbers 272738 and 232342, when divided by n, a two digit number, leave a remainder of 13 and 17 respectively. Find the sum of the digits of n?

Answer 1

Answer:

7

Step-by-step explanation:

Total Numbers = 2 (Given)

Number one = 272738 (Given)

Number two = 232342 (Given)

Since, the remainder is 13 and 17 so, the dividend must be greater than 17  

Therefore,

= 272738 = n × a + 13

= 272725 = n × a ---(1) and

= 232342 = n × b+17

= 232325 = n × b ---(2)

The last two digits of equation (1) and (2) are 25, thus n must be 25, and no other two digit number greater than 25 satisfies this.

Thus,

272725 = 25 × 10909

232325 = 25 × 9293

n=25, and the sum of digits of n = 2+5 = 7

Thus, the sum of digits of n is 7.