Math, asked by tejaswinidas410, 1 year ago

The numbers 28, 22, 'x', 'y', 4 are in arithmetic progression. What are the respective values of 'x' and 'y'?
A) 10, 16 B) 20, 18 C) 18, 16 D) 16, 10

Answers

Answered by asper1
18
common difference is equal to 28 minus 22 is equal to 6
so x is equal to 22 minus 6 is equal to 16
Y is equal to 16 minus 6 is equal to 10
Answered by vinod04jangid
1

Answer:

x = 16 and y = 10.

Step-by-step explanation:

Given:- Numbers in A.P. are 28, 22, x, y, 4

To Find:- Values of x and y.

Solution:-

A.P. is 28, 22, x, y, 4.

First term = 28, common difference = 22 - 28 = -6

As we know, if First term = a , common difference = d, then

Second term = a + d,

Third term = a + 2d

Fourth term = a + 3d.

In this series, x is the 3rd term, so

x = a + 2d

  = 28 + 2 × (-6)

  = 28 - 12

  = 16

In the given series, y is the 4th term, so

y = a+ 3d

  = 28 + 3 × (-6)

  = 28 - 18

  = 10

Hence the value of x = 16 and y = 10.

Therefore the series becomes 28, 22, 16, 10, 4.

#SPJ3

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