Question

The numbers 30 and 110 are found in the sequence u subscript n = n(n − 1). In which position is each number found ?

Answer 1

SOLUTION

GIVEN

The numbers 30 and 110 are found in the sequence

$\sf{u_n = n(n - 1)}$

TO DETERMINE

In which position is each number found

EVALUATION

Here the given sequence is

$\sf{u_n = n(n - 1)}$

We see that the n th term of the sequence is product of n and n - 1

Now

30 = 6 × 5

Thus we have

$\sf{30 =6 \times 5 = 6 \times (6 - 1) =u_6 }$

Hence 6th term of the sequence = 30

Again 110 = 11 × 10

$\sf{110 =11 \times 10 = 11 \times (11 - 1) =u_{11}}$

Hence 11th term of the sequence = 110

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If the middle term of a finite AP with 7 terms is 21 find the sum of all terms of the AP

https://brainly.in/question/30198388

2. find the 100th term of an AP whose nth term is 3n+1

https://brainly.in/question/22293445

3. 2,7,12,17,...sum of 12 terms of this A. P. is

https://brainly.in/question/24134044