the numbers are in 2:3:4 the sum of their cubes is 33957 find the number
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let the numbers be 2x,3x,4x
(2x)^3+ (3x)^3 + (4x)^3=33957
8(x)^3+27(x)^3+64(x)^3=33957
99(x)^3=33957
x^3=33957/99
x^3=343
x=7
the numbers are 14;21;28
(2x)^3+ (3x)^3 + (4x)^3=33957
8(x)^3+27(x)^3+64(x)^3=33957
99(x)^3=33957
x^3=33957/99
x^3=343
x=7
the numbers are 14;21;28
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Answer:
14,21,28
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