Question

. The numbers are in the ratio 7:5. When '1' is subtracted
from the first and '1' is added to the second the ratio
becomes 4:3. The numbers are​

Answer 1

Answer:

49 and 35 are the required numbers.

Step-by-step explanation:

Given :-

Two numbers are in the ratio 7 : 5. When 1 is subtracted to the first number and 1 is added to the second number, the ratio becomes 4 : 3

To find :-

The two numbers

Solution :-

Let the first number be 7x and the second number be 5x.

ATP,

$\frac{7x-1}{5x+1}$ = $\frac{4}{3}$

Cross multiply,

3(7x - 1) = 4(5x + 1)

21x - 3 = 20x + 4

21x - 20x = 4 + 3

x = 7

The two numbers are,

7x = 49

5x = 35

Verification :-

$\frac{7x-1}{5x+1}$ = $\frac{4}{3}$

Substitute the value of x,

$\frac{7(7)-1}{5(7)+1}$ = $\frac{48}{36} = \frac{12}{9} = \frac{4}{3}$

Hence, verified !

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The ratio of two number are 5:6. When 5 subtracted from both ratio become 4:5. Find the numbers

Answer 2

The numbers are 49 and 35

Step-by-step explanation:

Given that,

Two numbers are in the ratio 7:5

Let the first number be 7x

Let the second number be 5x

On subtracting 1 to the first and adding 1 to the second ratio becomes 4:3

Therefore

$\huge \frac{7x \: - \: 1}{5x \: + \: 1} = \frac{4}{3}$

$3 \times 7x - 1 = 4 \times5x + 1$

$\: \: \: \: \: \: 21x - 3 = 20x + 4$

$\: 21x - 20x = 4 + 3$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 7$

Thus,

First number = 7x = 7(7) = 49

Second number = 5x = 5(7) = 35

Thus the numbers are 49 and 35