The numbers from 101 to 150 are written as, 101102103104105…146147148149150. What will be the remainder when this total number is divided by 3?
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1(01) 1(02) 1(03)................1(50)
sum of the digit = 1325
1325/9 remainder is 2.
(or)
101 102 103 104..... 150
sum of the digit = 150*151/2 - 50*51/2;
= 11325 - 5050
= 6275/9
remainder is 2
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