Question

The numbers from 101 to 150 are written as, 101102103104105…146147148149150. What will be the remainder when this total number is divided by 3?

Answer 1

Answer:

1(01) 1(02) 1(03)................1(50)

sum of the digit = 1325

1325/9 remainder is 2.

(or)

101 102 103 104..... 150

sum of the digit = 150*151/2 - 50*51/2;

= 11325 - 5050

= 6275/9

remainder is 2