the numbers of all possible natural numbers using digits 9,8 and 0 when repetition of digits is not allowed as
Answers
Answer:
The given digits are 7,0,6 and repetition of digits is not allowed.
The one-digit numbers that can be formed are 7 and 6.
We are required to write 2−digit numbers.
Out of the given digits, the possible ways of choosing the two digits are
7,0;6,0;6,7
Using the digits 7 and 0, the numbers are 70.
Similarly, Using the digits 6 and 7, the numbers are 67 and 76.
Hence, all possible 2−digit numbers are
60,70,67,76
Now, we are required to write 3−digit numbers using the digits 7,0,6 and the repetition of the digits is not allowed. Keeping 0 at unit's place, 3−digit number obtained are 670 and 760.
Keeping 6 at unit's place, 3−digit number obtained are 706.
Keeping 7 at unit's place, 3−digit number obtained are 607.
Hence ,all possible 3−digit numbers are: 670,764,706 and 607.
All possible numbers using the digits 7,0 and 6 are
6,7,76,67,70,60,706,607,760,670. I hope you help you
Step-by-step explanation:
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Answer:
Answer is 4
Reason-9,0,8
=980,908
=890,809