Math, asked by ushaprasadgupta879, 9 months ago

The numberx is more than the numbery.if the sum of the squares of x and y is 34; find the productvof x and y.

Answers

Answered by ʙʀᴀɪɴʟʏᴡɪᴛᴄh

Given

x = y + 2

x² + y² = 34

x - y = 2

squaring, (x - y)² = 2²

x² + y² - 2 x y = 4

34 - 2 x y = 4

x y = 15

===========================

2x - 3y = 10 x y = 16

8x³ - 27 y³ = (2x - 3y) ( 4x² + 6 xy + 9 y²)

= (2 x - 3y) [ (2x -3y)² + 18 xy ]

= 10 * [ 10² + 18 * 16 ]

====================================

x > 0 and x² + 1/9x² = 25 / 36

(x + 1/3x)² = x² + 1/9x² + 2/3 = 25/36 + 2/3

(x + 1/3x)² = 49/36

x + 1/3x = 7/6 , we drop the negative value as x > 0.

x³ + 1/27x³ = (x + 1/3x) ( x² + 1/9x² - x/3x)

= 7/6 * (25/36 - 1/3)

= 7/6 * 1/36

= 7/216

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Answered by dinnice4u

Number is 3 and 5
Sum of square is 9+ 25 = 34
So product is 3* 5 = 15

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The numberx is more than the numbery.if the sum of the squares of x and y is 34; find the productvof x and y.​

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The numberx is more than the numbery.if the sum of the squares of x and y is 34; find the productvof x and y.