Question

The numeraotor of a fraction is greater then its denomintor by 8 .If numerator is decreased by 17 and numerator is increase by 1 .The number obtained is 3/2 .Find the number .


I REQUEST PLZ DON'T SPAM AND PLZ DONT COPY THE ANSWER FROM G00GLE

Answer 1

Answer:

Numerator is x+4=41+4=45 and denominator is x=41

Step-by-step explanation:

MISTAKE IN QUESTION

It will be if denominator is decreased in place of numerator

There are two attached files for the solution..

Answer 2

$\large\underline{\underline{\pink{☢{\red{\pmb{\sf{ \:Given :-}}}}}}}$

➬ The denominator of a fraction is greater then it's numerator by 8.

➬ If numerator is increased by 17 and denominator is increased the 1 . we get 3/2.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\underline{\underline{\pink{☢{\red{\pmb{\sf{ \:To \: Find :-}}}}}}}$

➬ Find the original number .

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\underline{\underline{\pink{☢{\red{\pmb{\sf{ \:Solution :-}}}}}}}$

❒ According to Question :

➳ The denominator of a fraction is greater then it's numerator by 8. So,

$\huge\blue{\star \: \: \: \: \: \: {\orange{\bf{ \dfrac{x}{x + 8}}}}}$

➳ If numerator is increased by 17 and denominator is increased the 1 . we get 3/2.So,

$\huge\blue{\star \: \: \: \: \: \: {\orange{\bf{ \dfrac{x + 17}{x + 9} = \dfrac{3}{2}}}}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━

❒ Cross Multiplication :

${:\implies{\sf{2( x + 17) = 3(x + 9)}}}$

${:\implies{\sf{2 x + 34 = 3x + 27}}}$

${:\implies{\sf{ 34 - 27= 3x - 2x}}}$

$\large{\blue{:\longmapsto{\sf{X = {\underline{\orange{\sf{7}}}}}}}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━

❒ Original Fraction :

Numerator :

$\large{\orange{\dashrightarrow{\underline{\underline{\green{\sf{Numerator = x = 7}}}}}}}$

Denominator :

$\large{\orange{\dashrightarrow{\underline{\underline{\green{\sf{Denominator = x + 8 = 7 + 8 = 15}}}}}}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━

❒ Therefore :

$\large\orange{\underline{\underline\color{cyan}{\frak{Original Fraction = \dfrac{7}{15}}}}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━