Question

The numerator and the denominator of a fraction are in the ratio 3:2. I 3 is added to the numerator and 2 is subtracted from the denominator, a new fraction is formed whose value is Find the original fraction

Answer 1

$\huge\green{\underline{✪Solution}}$

Let the fraction be 3x/2x.

$\frac{(3x+3)}{(2x-2)}$$\frac{=9}{4}$

or,

$12x+12 = 18x-18$

or,

$18x-12x = 18+12 = 30$

$6x = 30$

or,

$x = 5$

The fraction is $\frac{15}{10}$

Check

$\frac{(15+3)}{(10–2)}$

$= 18/8 = 9/4$

Answer 2

❤[Answer]❤

Let the numerator be x and denominator be y.

$\frac{x}{y} = \frac{3}{2} = > 2x = 3y$

according to the question :

$\frac{x + 3}{y - 2} = \frac{9}{4}$

$4x + 12 = 9y - 18$

$4x + 30 = 9y$

Substitute the value of x in terms of y

$4 \times \frac{3}{2}y + 30 = 9y$

$6y + 30 = 9y$

$3y = 30$

$y = 10$

$x = \frac{3}{2} \times (10) = 15$

$therfore \: fraction \: is \: \frac{15}{10}$

Hope it helps uhh❣❣

Mark as brainliest plz❣❣