Math, asked by llEmberMoonblissll, 1 month ago

The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction.​

Answers

Answered by TheBlood
6

Let the values,

Numerator = ( X - 8 )

Denominator = X

Fraction = Numerator/Denominator = ( X -8)/X.

When 3 is added to the numerator and 3 is subtracted from the denominator the fraction obtained is 3/4

X - 8 + 3 / X - 3 =3 /4

X-5/X-3 = 3/4

4X-20 = 3X-9

X = 11

So,(X-8)/X = (11-8)/11

Answer is 3/11

Answered by SANDHIVA1974
2

Answer:

 \large \dag Question :-

The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction.

 \large \dag Answer :-

\red\dashrightarrow\underline{\underline{\sf  \green{The   \: Original \:  Fraction  \: is \:  \frac{3}{11} }} }\\

 \large \dag Step by step Explanation :-

Let Numerator and Denominator of Original Fraction be :

Numerator = x

As Per the question numerator of the fraction is 8 less than the denominator so,

Denominator should be = x + 8

So ,

\text{Original Fraction = } \frac{\text x}{\text x + 8}  \\

❒ When 3 is added to the numerator and 3 is subtracted from the denominator :

 \rm \text{Fraction Becomes } :  \frac{x + 3}{x + 5}  \\ 

⏩ According To Question :

 \large \blue \bigstar  \:   \red{ \bf  \frac{x + 3}{x + 5} =  \frac{3}{4}  } \\

:\longmapsto \rm 4(x + 3) = 3(x + 5 )\\

:\longmapsto \rm 4x + 12 = 3x + 15 \\

:\longmapsto \rm 4x - 3x = 15 - 13 \\

\purple{ \large :\longmapsto  \underline {\boxed{{\bf x = 3} }}}

\blue\dashrightarrow\underline{\underline{\sf  \orange{Numerator  \: of \:  Original  \: Fraction = 3 }} }\\

☆ As numerator of the fraction is 8 less than the denominator

\rm\therefore \:  Denominator  = 3   + 8\\

\blue\dashrightarrow\underline{\underline{\sf  \orange{Denominator  \: of \:  Original  \: Fraction = 11 }} }\\

Therefore,

\large\underline{\pink{\underline{\frak{\pmb{ Original  \: Fraction  =  \dfrac{3}{11} }}}}}

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