The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction.
Answers
Let the values,
Numerator = ( X - 8 )
Denominator = X
Fraction = Numerator/Denominator = ( X -8)/X.
When 3 is added to the numerator and 3 is subtracted from the denominator the fraction obtained is 3/4
X - 8 + 3 / X - 3 =3 /4
X-5/X-3 = 3/4
4X-20 = 3X-9
X = 11
So,(X-8)/X = (11-8)/11
Answer is 3/11
Answer:
Question :-
The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction.
Answer :-
Step by step Explanation :-
Let Numerator and Denominator of Original Fraction be :
Numerator = x
As Per the question numerator of the fraction is 8 less than the denominator so,
Denominator should be = x + 8
So ,
❒ When 3 is added to the numerator and 3 is subtracted from the denominator :
⏩ According To Question :
☆ As numerator of the fraction is 8 less than the denominator
Therefore,