The numerator of a fraction decreased by 20% and the denominator is increased by 20%. The resultant fraction represents what percent decrease over the original fraction ?
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HEY Buddy....!! here is ur answer
Let the fraction = x/y
According to the question.....................(x*80/100)/(y*120/100)
=> x*80/y*120
=> 2x/3y
Now, Percent decreased over the original fraction = [(x/y)–(2x/3y]/(x/y) × 100
=> [(3x–2x)/3y]/(x/y) × 100
=> (x/3y)/(x/y) × 100
=> 100/3
=> 33.33%
Thus, the resultant fraction decreased by 33.33%
I hope it will be helpful for you...!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
Let the fraction = x/y
According to the question.....................(x*80/100)/(y*120/100)
=> x*80/y*120
=> 2x/3y
Now, Percent decreased over the original fraction = [(x/y)–(2x/3y]/(x/y) × 100
=> [(3x–2x)/3y]/(x/y) × 100
=> (x/3y)/(x/y) × 100
=> 100/3
=> 33.33%
Thus, the resultant fraction decreased by 33.33%
I hope it will be helpful for you...!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
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