the numerator of a fraction is 2 less than it's denominator.if 2 is added to this fraction of becomes 8/3.find the original fraction
Answers
Answered by
16
let the denominator is x the numerator is x-2
fraction = x-2/x
according to question if 2 is added to the fraction
new fraction = x-2+2/x+2= 8/3
=>3x = 8(x+2)
=>3x-8x = 16
=>x=- 16/5
fraction =-16/5-2÷16/5
=-26/16
fraction = x-2/x
according to question if 2 is added to the fraction
new fraction = x-2+2/x+2= 8/3
=>3x = 8(x+2)
=>3x-8x = 16
=>x=- 16/5
fraction =-16/5-2÷16/5
=-26/16
Answered by
5
Answer:
2/3
Step-by-stepet the denominator is x the numerator is x-2
fraction = x-2/x
according to question if 2 is added to the fraction
new fraction = x-2+2/x+2= 8/3
=>3x = 8(x+2)
=>3x-8x = 16
=>x=- 16/5
fraction =-16/5-2÷16/5
=-26/16
further simply then you will get 2/3
Similar questions