The numerator of a fraction is 2 less than its denominator if one is added to both its numerator and denominator it become 2/3 find the fraction
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Let the denominator be x.
Then numerator =x-2.
Required fraction is x-2/x.
Since, 1 is added to both numerator and denominator.
Then,
(x-2+1)/x=2/3
By cross multiplying
3(x-2+1)=2(x+1)
3x-6+3=2x+2
3x-3=2x+2
3x-2x=2+3
X=5 (denominator)
Therefore, numerator =x-2
=5-2
=3
Thus, the required fraction is 3/5.
Then numerator =x-2.
Required fraction is x-2/x.
Since, 1 is added to both numerator and denominator.
Then,
(x-2+1)/x=2/3
By cross multiplying
3(x-2+1)=2(x+1)
3x-6+3=2x+2
3x-3=2x+2
3x-2x=2+3
X=5 (denominator)
Therefore, numerator =x-2
=5-2
=3
Thus, the required fraction is 3/5.
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