Question

The numerator of a fraction is 3 less than denominator
. If 1 is added to both its numerator and denominator it becomes 2 / 3 . Find fraction. PLEASE DO IT FASTLY . TOMORROW IS MY TEST

Answer 1

Here is your answer...

hope it help you...

Answer 2

Answer:

The fraction is $\frac{5}{8}$

Step-by-step explanation:

Let the numerator be N and denominator be D

So, the required fraction will be $\frac{N}{D}$

According to question,

The numerator of a fraction is 3 less than denominator, that is ,

N = D - 3

So, the new fraction is $\frac{D-3}{D}$

Also, it is given that if 1 is added to both its numerator and denominator it becomes 2 / 3

Therefore now,

$\frac{D-3+1}{D+1} = \frac{2}{3}$

$\frac{D-2}{D+1} = \frac{2}{3}$

3 ( D - 2 ) = 2 ( D + 1 )

3 D - 6 = 2 D + 2

3 D - 2 D = 2 + 6

D = 8

We know,

N = D - 3

N = 8 - 3 = 5

So the fraction $\frac{N}{D}$ = $\frac{5}{8}$

Hence,

The fraction is  $\frac{5}{8}$