Question

⭐The numerator of a fraction is 3 less than it's denominator, the fraction is decreased by 1/15.Find the Fraction.⭐

CLASS 10 CHAPTER :QUADRATIC EQUATIONS

❌NO SPAM ❌

BEST ANSWER WILL BE MARKED AS BRAINLIEST!

Answer 1

REFER THE ATTACHMENT.

Answer 2

$\huge{\mathfrak{heya!!}}$
.
.
➖➖➖➖➖➖➖➖⬇️

let the denominator be x

According to question,

numerator is 3 less than the denominator ,

so the numerator = x-3


hence the fraction becomes.
$\frac{x - 3}{x}$


ATQ,


If 1 is added to both the fraction is decresed by 1/15.

$\frac{x - 3 + 1}{x + 1} = \frac{x - 3}{x} - \frac{1}{15}$

$\frac{x - 2}{x + 1} = \frac{15(x - 3) - x}{15x}$

$\frac{x - 2}{x + 1} = \frac{15x - 45 - x}{15x}$


$15x(x - 2) = (14x - 45)(x + 1)$

${15x}^{2} - 30x = {14x}^{2} + 14x - 45x - 45$

${x}^{2} + 61x + 45 = 0$