Question

the numerator of a fraction is 3 less than its denominator if 1 is added to both its numerator and denominator it becomes half find the fraction​

Answer 1

Step-by-step explanation:

Let the denominator of the fraction be x

So the numerator will be x-3

Original fraction =x-3/x

If 1 is added to both its numerator and denominator,

New numerator = x-3+1=x-2

New denominator=x+1

New fraction=x-2/x+1

The new fraction becomes half so

x-2/x+1=1/2

2(x-2) =1(x+1) (Cross multiplication)

=2x - 4 = x +1

=2x-x=1+4

=1x=5

Original numerator=x-3=5-3=2

Original denominator=x=5

The fraction is = 2/5

Hope it will help you.

Please follow me and mark me as the brainliest.

Answer 2

$\huge\underline\mathtt\purple{Question}$

★ The numerator of a fraction is 3 less than its denominator if 1 is added to both of its numerator and denominator, it becomes half. Find the fraction.

$\huge\underline\mathtt{Answer}$

$\large\mathrm{The\:fraction\:required\:is\: \frac{2}{5}}$

$\huge\underline\mathtt\red{Solution}$

= $\large\mathtt{Let\:the\:denominator\:to\:be\:x}$

= $\large\mathtt{Let\:the\:numerator\:to\:be\:(x - 3)}$

= According to question ( A.T.Q)

= $\large\mathtt{\frac {x-3+1}{x-1} = \frac {1}{2}}$

= $\large\mathtt{\frac {x-2}{x+1} = \frac {1}{2}}$

= $\large\mathtt{2(x-2) = 1(x+1)}$

= $\large\mathtt{2x-4 = x+1}$

= $\large\mathtt{2x-x = 1+4}$

= $\large\mathtt{x = 5}$

★ Putting this value to find denominator and numerator.

« Denominator = x = 5

« Numerator = (x – 3) = (5 – 3) = 2

$\huge\mathtt{\therefore The\:fraction\:will\:be\: \frac {2}{5}}$

_______________________________

Thankaa!!