the numerator of a fraction is 3 less than its denominator. if the denominator is increased by 5 and the numerator by 2 , we get 1/2.find the fraction.
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Let the numerator be 'x' and denominator be 'y'
A/Q --> x =y - 3, fraction --> (y - 3)/y
Now, numerator = y - 3 + 2 = y - 1
denominator = y + 5
Fraction -> (y - 1)/(y + 5) = 1/2
2y - 2 = y + 5
y = 7
x = 7 - 3 = 4
Required fraction --> 4/7
Hope This Helps You!
A/Q --> x =y - 3, fraction --> (y - 3)/y
Now, numerator = y - 3 + 2 = y - 1
denominator = y + 5
Fraction -> (y - 1)/(y + 5) = 1/2
2y - 2 = y + 5
y = 7
x = 7 - 3 = 4
Required fraction --> 4/7
Hope This Helps You!
Answered by
0
Let fraction is x-3/x.A.T.Q x-3+2/x+5=1\2,x-1\x+5=1/2,x=7 so fraction is x-3/x=7-3/7=4/7
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