The numerator of a fraction is 3 less than its denominator. if the numerator is increased by 1 and the denominator is increased by 3. the value of the fraction obtained is 1/2. what was the original fraction?
Answers
Answered by
1
let the numerator be x and denominator be y then the equation we get is
x=y-3 ........1
the new fraction that we get is
x+1/y+3=1/2
Putting value of x from 1
y-2/y+3=1/2
2y-4=y+3
y=7 and using 1,we have x=4
and the original fraction was
x/y=4/7
x=y-3 ........1
the new fraction that we get is
x+1/y+3=1/2
Putting value of x from 1
y-2/y+3=1/2
2y-4=y+3
y=7 and using 1,we have x=4
and the original fraction was
x/y=4/7
Similar questions