Question

The numerator of a fraction is 3 less than its denominator if 2 is added to both numerator and denominator the sum of new fraction and original fraction is 29/30 find the original fraction.​

Answer 1

Answer:

(x-3)/x=11/72

Step-by-step explanation:

Let the denominator be x

So, Numerator  is x-3

We got fraction,

$\frac{x}{x-3}$

According to question, when 2 is added to numerator and denominator,

Then, we get = (x-1)/(x+2)

So,

=> (x-3)/x +(x-1)/(x+2)= 29/30

=> (x-3)((x+2) +x(x-1)

=> x(x+2)*29/30

⇒    (x²-6-x + x²-x)20= 29x²+58x

⇒    40x²-120-40x=29x²+58x

⇒    11x²-98x- 120=0

⇒    11x² - 110x +12x -120=0

⇒     (11x+12)(x-10)=0

We will have to cancel the negative fraction value  of x.

=> X = 11

We have the fraction,

=> (x-3)/x=11/72

Answer 2

ANSWER:---------

x

------

x

-------,

y

x-3

--------

x-3

x+3 x

x+3-3

{3and -3 will be canceled)

now fraction=

x-3+2

------------=29/20

x+2

(2x²-2×-6)

------------------=29/20

2²+2x

40×x²-40x-20=29x²+58x

11x - 98 x -1²o =O

a(a²)+(b(x+c)=O

x= -6 ²-4(66)+divided by 2

x=-98=14(88⁴) divided by 2²

x=98+2²

--------------answer=22²/22=10

2²

x=98-122

-----------------answer=24/72=-12/11

2²

HENCE, PROVED,

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