Question

The numerator of a fraction is 3 less than the denominator. If 2 is added to both the
numerator and the denominator, then the sum of the new fraction and the original
fraction is 29/20. Find the original fraction.
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Answer 1

Answer:

14/20

Step-by-step explanation:

if we count numerator as x and denominator as x

so, x-3 / y + 2/1

then the new fraction is 29 / 20 so it is 29- 3=26

26/20- 2/1=40/20-26/20=14/20

so our, original fraction is 14/20

Answer 2

Answer:

Let the fraction be $\frac{x-3}{x}$

$\frac{x-1}{x+2} +\frac{x-3}{x} =\frac{29}{20} \\\frac{x^2-x+x^2-x-6}{x^2+2x} =\frac{29}{20} \\(2x^2-2x-6)20=29x^2+58x\\40x^2-40x-120=29x^2+58x\\11x^2-98x-120=0$

By solving we get x=10

Thus fraction=$\frac{7}{10}$

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