Question

the Numerator of a fraction is 3 less than the denominator. If 2
is added to both the Numerator and denominator then the Sum
the new feaction and
original fraction is 29/20 find the orignal fraction​

Answer 1

Answer:

X-3/X It is original fraction

New fraction is X-3+2/X+2=X-1/X+2

new fraction is X-1/X+2

now add original fraction and new fraction

X-3/X + X-1/X+2 =29/20

$\frac{{2x}^{2} - 2x - 3}{ {x}^{2} + 2 } = \frac{29}{20}$

$20({2x}^{2} - 2x - 3) = 29( {x}^{2} + 2x$

$40 {x}^{2} - 40x - 120 = 29 {x}^{2} + 58x$

$40 {x}^{2} - 29 {x}^{2} - 58x - 40x - 120 = 0$

$11 {x}^{2} - 98x - 120 = 0$

if we factoriz this above one we get X=10, X= -1. 0909

so that we have to choose X=10

then original factor is X-3/X

that means 10-3/10=7/10

Answer is 7/10