Question

The numerator of a fraction is 3 less than the denominator. If the numerator and denominator are
both increased by 2, the new fraction becomes6/7
Find the original fraction.
​

Answer 1

Answer:

Let the denominator be x.

Numerator =x-3

Original fraction=x-3/x

According to question,

x-3+2/x+2=6/7

x-1/x+2=6/7

6(x+2)=7(x-1)

6x+12=7x-7

6x-7x=-7-12

-x=-19

x=19

Original fraction=16/19

Answer 2

${ \huge{ \underline{ \underline{ \sf{ \green{GivEn : }}}}}}$

• Numerator is 3 less than the denominator.

• If two is added to both numerator and denominator the fraction becomes 6/7.

${ \huge{ \underline{ \underline{ \sf{ \green{To \: find :}}}}}}$

What's the original fraction?

${ \huge{ \underline{ \underline{ \sf{ \green{SoluTion : }}}}}}$

Let the denominator be x

Given that,

Numerator is 3 less than the denominator.

Therefore, the numerator will be x - 3

Again, it's given that

If two is added to both numerator and denominator the fraction becomes 6/7.

According to the question :-

⟶ x -1/x+2 = 6/7

⟶ (x -1) ×7 = 6(x+2)

⟶ 7x -7 = 6x +12

⟶ 7x - 6x = 12 +7

⟶ x = 19

Hence, denominator is = 19

Numerator

= (x- 3)

= 19 -3

= 16

Therefore, the original fraction is = 16/19