the numerator of a fraction is 3 less than the denominator. if both the nmerator and denominator are increased by 2 , the new fraction becomes 6/7 . find the original fraction
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Let the denominator of the fraction be X.
Then the numerator of the fraction = (X-3)
Fraction = Numerator/Denominator = X-3/X.
The and denominator are increased by 2 then the Numerator and denominator become (X-3+2) and (X+2).
Fraction = Numerator/Denominator =(X-3+2)/(X+2).
According to the question,
(X-3+2)/(X+2) = 6/7
X-1/X+2 = 6/7
7(X-1) = 6(X+2)
7X-7 = 6X+12
7X-6X= 12+7
X = 19
Numerator = (X-3) = (19-3) = 16
And, Denominator =(X) = 19
Therefore,
Original Fraction = Numerator/Denominator = (X-3)/X= 19/16 .\
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