Question

The numerator of a fraction is 3 less than the denominator. If 2 is added to both the new fraction and original fraction is 29/20. find the original fraction​

Answer 1

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Answer 2

ANSWER ⤵️

Let the fraction be x−3/x

By the given condition, new fraction= x−3+2/x+2

= x−1/x+2

x-3/x + x-1/x+2 = 29/20

⇒20[(x−3)(x+2)+x(x−1)]=29(x²+2x)

⇒20[x²−x−6+x²−x]=29x²+58x

⇒20[2x²−2x−6]=29x²+58x

⇒40x²−40x−120−29x²−58x=0

⇒11x²−98x−120=0

⇒11x²−110x+12x−120=0

⇒11x(x−10)+12(x−10)=0

⇒(x−10)(11x+12)=0

⇒x=10

∴x= -12/11 is rejected

∴ the fraction is 7/10